What is the answer to solvefor t,A=P(1+r)^t ?

The answer to solvefor t,A=P(1+r)^t is t=(ln(A/P))/(ln(1+r))

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solvefor t,A=P(1+r)^t

solve for

t, A = P (1 + r)^{t}

t = \frac{ln ( \frac{A}{P} )}{ln ( 1 + r )}

Solution steps

A = P (1 + r)^{t}

Switch sides

P (1 + r)^{t} = A

Divide both sides by

P

(1 + r)^{t} = \frac{A}{P}

Apply exponent rules

t ln (1 + r) = ln (\frac{A}{P})

Solve

t ln (1 + r) = ln (\frac{A}{P}) : t = \frac{ln ( \frac{A}{P} )}{ln ( 1 + r )}

t = \frac{ln ( \frac{A}{P} )}{ln ( 1 + r )}

3^{x} = 2^{x + 3}

0.5 = 320 e^{- 3.1 t}

5^{2 x + 1} - 6 (5 x) + 1 = 0

9^{x} = 729

7^{x + 3} = e^{x}

What is the answer to solvefor t,A=P(1+r)^t ?
The answer to solvefor t,A=P(1+r)^t is t=(ln(A/P))/(ln(1+r))