What is the answer to 3^{2x-1}=4^{3x} ?

The answer to 3^{2x-1}=4^{3x} is x=(ln(3))/(2(ln(3)-3ln(2)))

Solve for x: 3^{2x-1}=4^{3x}

The solution is x=(ln(3))/(2(ln(3)-3ln(2)))

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3^{2 x - 1} = 4^{3 x}

x = \frac{ln ( 3 )}{2 ( ln ( 3 ) - 3 ln ( 2 ) )}

Decimal Notation

x = - 0.56004 \dots

Solution steps

3^{2 x - 1} = 4^{3 x}

Apply exponent rules

(2 x - 1) ln (3) = 3 x ln (4)

Solve

(2 x - 1) ln (3) = 3 x ln (4) : x = \frac{ln ( 3 )}{2 ( ln ( 3 ) - 3 ln ( 2 ) )}

x = \frac{ln ( 3 )}{2 ( ln ( 3 ) - 3 ln ( 2 ) )}

x, 2^{x} - 2^{y} = 2016

4^{x + 2} = 7^{x - 1}

5^{x + 7} = 3

n = 4^{x}

2^{x} e^{3 x + 1} = 10

What is the answer to 3^{2x-1}=4^{3x} ?
The answer to 3^{2x-1}=4^{3x} is x=(ln(3))/(2(ln(3)-3ln(2)))
Solve for x: 3^{2x-1}=4^{3x}
The solution is x=(ln(3))/(2(ln(3)-3ln(2)))