What is the answer to 8^{x+1}=43 ?

The answer to 8^{x+1}=43 is x=(ln(43))/(3ln(2))-1

Solve for x: 8^{x+1}=43

The solution is x=(ln(43))/(3ln(2))-1

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8^{x + 1} = 43

x = \frac{ln ( 43 )}{3 ln ( 2 )} - 1

Decimal Notation

x = 0.80875 \dots

Solution steps

8^{x + 1} = 43

Apply exponent rules

(x + 1) ln (8) = ln (43)

Solve

(x + 1) ln (8) = ln (43) : x = \frac{ln ( 43 )}{3 ln ( 2 )} - 1

x = \frac{ln ( 43 )}{3 ln ( 2 )} - 1

4^{2 x - 1} = 64

4^{x - 1} = 2^{x + 2}

2^{5 x + 15} = 4^{10 x + 5}

e^{0.05 x} = 3

What is the answer to 8^{x+1}=43 ?
The answer to 8^{x+1}=43 is x=(ln(43))/(3ln(2))-1
Solve for x: 8^{x+1}=43
The solution is x=(ln(43))/(3ln(2))-1