What is the answer to -3*10^{2t}=-28 ?

The answer to -3*10^{2t}=-28 is t=(ln(28/3))/(2ln(10))

Solve for t: -3*10^{2t}=-28

The solution is t=(ln(28/3))/(2ln(10))

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- 3 \cdot 1 0^{2 t} = - 28

t = \frac{ln ( \frac{28}{3} )}{2 ln ( 10 )}

Decimal Notation

t = 0.48501 \dots

Solution steps

- 3 \cdot 1 0^{2 t} = - 28

Divide both sides by

- 3

1 0^{2 t} = \frac{28}{3}

Apply exponent rules

2 t ln (10) = ln (\frac{28}{3})

Solve

2 t ln (10) = ln (\frac{28}{3}) : t = \frac{ln ( \frac{28}{3} )}{2 ln ( 10 )}

t = \frac{ln ( \frac{28}{3} )}{2 ln ( 10 )}

0 = - 3^{2 x} + 2

2 5^{x} + 1 = 26 (5^{x - 1})

5^{x} - 5^{(5 - x)} = 150

4^{x} = 89

2^{x + 3} - 2^{x} = k (x) (2^{x})

What is the answer to -3*10^{2t}=-28 ?
The answer to -3*10^{2t}=-28 is t=(ln(28/3))/(2ln(10))
Solve for t: -3*10^{2t}=-28
The solution is t=(ln(28/3))/(2ln(10))