What is the answer to 10^{x+2}=5 ?

The answer to 10^{x+2}=5 is x=(ln(5))/(ln(10))-2

Solve for x: 10^{x+2}=5

The solution is x=(ln(5))/(ln(10))-2

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1 0^{x + 2} = 5

x = \frac{ln ( 5 )}{ln ( 10 )} - 2

Decimal

x = - 1.30102 \dots

Solution steps

1 0^{x + 2} = 5

Apply exponent rules

(x + 2) ln (10) = ln (5)

Solve

(x + 2) ln (10) = ln (5) : x = \frac{ln ( 5 )}{ln ( 10 )} - 2

x = \frac{ln ( 5 )}{ln ( 10 )} - 2

e^{3 - 4 x} = 7

1 0^{l o g_{10} (x^{2} + x)} = 20

8^{x} = 9^{x - 1}

3 2^{n} = 2

e^{7 - 4 x} = 2

What is the answer to 10^{x+2}=5 ?
The answer to 10^{x+2}=5 is x=(ln(5))/(ln(10))-2
Solve for x: 10^{x+2}=5
The solution is x=(ln(5))/(ln(10))-2