What is the answer to 27^{x+4}=(1/9)^{x-1} ?

The answer to 27^{x+4}=(1/9)^{x-1} is x=-2

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27^{x+4}=(1/9)^{x-1}

2 7^{x + 4} = (\frac{1}{9})^{x - 1}

x = - 2

Solution steps

2 7^{x + 4} = (\frac{1}{9})^{x - 1}

Apply exponent rules

3 (x + 4) = - 2 (x - 1)

Solve

3 (x + 4) = - 2 (x - 1) : x = - 2

x = - 2

3 2^{2 c} = 8^{c + 7}

1 0^{x} = 1000000

y, x^{y} = x y

2^{x + \frac{9}{2}} = 42

2^{x} = 2 (5^{x})

What is the answer to 27^{x+4}=(1/9)^{x-1} ?
The answer to 27^{x+4}=(1/9)^{x-1} is x=-2
Solve for x: 27^{x+4}=(1/9)^{x-1}
The solution is x=-2