What is the answer to 2^x=2(5^x) ?

The answer to 2^x=2(5^x) is x=(ln(2))/(ln(2)-ln(5))

Solve for x: 2^x=2(5^x)

The solution is x=(ln(2))/(ln(2)-ln(5))

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2^{x} = 2 (5^{x})

x = \frac{ln ( 2 )}{ln ( 2 ) - ln ( 5 )}

Decimal Notation

x = - 0.75647 \dots

Solution steps

2^{x} = 2 (5^{x})

Apply exponent rules

x ln (2) = ln (2) + x ln (5)

Solve

x ln (2) = ln (2) + x ln (5) : x = \frac{ln ( 2 )}{ln ( 2 ) - ln ( 5 )}

x = \frac{ln ( 2 )}{ln ( 2 ) - ln ( 5 )}

4^{x + 1} = 3^{x}

8^{3 x + 1} = 3 2^{x}

9^{x} = 729

e^{z} + 1 = 0

8 x^{3} e^{- 2 x} - 4 x^{4} e^{- 2 x} = 0

What is the answer to 2^x=2(5^x) ?
The answer to 2^x=2(5^x) is x=(ln(2))/(ln(2)-ln(5))
Solve for x: 2^x=2(5^x)
The solution is x=(ln(2))/(ln(2)-ln(5))