What are the solutions to the equation 4x^2-24x+20=0 ?

The solutions to the equation 4x^2-24x+20=0 are x=5,x=1

Find the zeros of 4x^2-24x+20=0

The zeros of 4x^2-24x+20=0 are x=5,x=1

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4 x^{2} - 24 x + 20 = 0

x = 5, x = 1

Solution steps

4 x^{2} - 24 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 4 \cdot 20}{2 \cdot 4}

(- 24)^{2} - 4 \cdot 4 \cdot 20 = 16

x_{1, 2} = \frac{- ( - 24 ) \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 16}{2 \cdot 4}, x_{2} = \frac{- ( - 24 ) - 16}{2 \cdot 4}

x = \frac{- ( - 24 ) + 16}{2 \cdot 4} : 5

x = \frac{- ( - 24 ) - 16}{2 \cdot 4} : 1

The solutions to the quadratic equation are:

x = 5, x = 1

\frac{2 - 5}{2 + 5}

- 3 (z + 4)^{2} = - 108

\frac{9 ^{n}}{3 ^{2 n + 1}}

\frac{x}{3} > 4

(2^{- 4})^{- 3}

What are the solutions to the equation 4x^2-24x+20=0 ?
The solutions to the equation 4x^2-24x+20=0 are x=5,x=1
Find the zeros of 4x^2-24x+20=0
The zeros of 4x^2-24x+20=0 are x=5,x=1