What are the solutions to the equation -3(z+4)^2=-108 ?

The solutions to the equation -3(z+4)^2=-108 are z=2,z=-10

Find the zeros of -3(z+4)^2=-108

The zeros of -3(z+4)^2=-108 are z=2,z=-10

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- 3 (z + 4)^{2} = - 108

z = 2, z = - 10

Solution steps

- 3 (z + 4)^{2} = - 108

Divide both sides by

- 3

(z + 4)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 4 = 36 : z = 2

Solve

z + 4 = - 36 : z = - 10

The solutions to the quadratic equation are:

z = 2, z = - 10

\frac{9 ^{n}}{3 ^{2 n + 1}}

\frac{x}{3} > 4

(2^{- 4})^{- 3}

u^{2} + 3 u - 28 = 0

- 3.55 \leq - 28.4

What are the solutions to the equation -3(z+4)^2=-108 ?
The solutions to the equation -3(z+4)^2=-108 are z=2,z=-10
Find the zeros of -3(z+4)^2=-108
The zeros of -3(z+4)^2=-108 are z=2,z=-10