What are the solutions to the equation u^2+3u-28=0 ?

The solutions to the equation u^2+3u-28=0 are u=4,u=-7

Find the zeros of u^2+3u-28=0

The zeros of u^2+3u-28=0 are u=4,u=-7

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u^{2} + 3 u - 28 = 0

u = 4, u = - 7

Solution steps

u^{2} + 3 u - 28 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 28) = 11

u_{1, 2} = \frac{- 3 \pm 11}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 3 + 11}{2 \cdot 1}, u_{2} = \frac{- 3 - 11}{2 \cdot 1}

u = \frac{- 3 + 11}{2 \cdot 1} : 4

u = \frac{- 3 - 11}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

u = 4, u = - 7

- 3.55 \leq - 28.4

\frac{x ^{6}}{x ^{4}}

2 x^{5} - 32 y^{4} x

1 - \frac{a}{b}

(x^{- 1})^{2}

What are the solutions to the equation u^2+3u-28=0 ?
The solutions to the equation u^2+3u-28=0 are u=4,u=-7
Find the zeros of u^2+3u-28=0
The zeros of u^2+3u-28=0 are u=4,u=-7