What is the answer to 2^{x+1}=13 ?

The answer to 2^{x+1}=13 is x=(ln(13))/(ln(2))-1

Solve for x: 2^{x+1}=13

The solution is x=(ln(13))/(ln(2))-1

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2^{x + 1} = 13

x = \frac{ln ( 13 )}{ln ( 2 )} - 1

Solution steps

2^{x + 1} = 13

Apply exponent rules

(x + 1) ln (2) = ln (13)

Solve

(x + 1) ln (2) = ln (13) : x = \frac{ln ( 13 )}{ln ( 2 )} - 1

x = \frac{ln ( 13 )}{ln ( 2 )} - 1

x, h = 2^{x} - 1

5^{x - 1} + 5^{x - 2} = 30

5^{x + 4} \cdot 25 = 125

130 (5^{x - 2}) = 1 + 2 5^{x}

(\frac{3}{5})^{x} = 7^{1 - x}

What is the answer to 2^{x+1}=13 ?
The answer to 2^{x+1}=13 is x=(ln(13))/(ln(2))-1
Solve for x: 2^{x+1}=13
The solution is x=(ln(13))/(ln(2))-1