What is the answer to (3/5)^x=7^{1-x} ?

The answer to (3/5)^x=7^{1-x} is x=(ln(7))/(ln(21/5))

Solve for x: (3/5)^x=7^{1-x}

The solution is x=(ln(7))/(ln(21/5))

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(\frac{3}{5})^{x} = 7^{1 - x}

x = \frac{ln ( 7 )}{ln ( \frac{21}{5} )}

Solution steps

(\frac{3}{5})^{x} = 7^{1 - x}

Apply exponent rules

x ln (\frac{3}{5}) = (1 - x) ln (7)

Solve

x ln (\frac{3}{5}) = (1 - x) ln (7) : x = \frac{ln ( 7 )}{ln ( \frac{21}{5} )}

x = \frac{ln ( 7 )}{ln ( \frac{21}{5} )}

\frac{1 0 ^{2}}{1 0 ^{x}} = 10

2^{5 x} = 3^{x + 2}

5^{4 x - 1} = 25

r, x^{r} = 0

3^{x} 5^{x + 1} = 1 2^{x - 1}

What is the answer to (3/5)^x=7^{1-x} ?
The answer to (3/5)^x=7^{1-x} is x=(ln(7))/(ln(21/5))
Solve for x: (3/5)^x=7^{1-x}
The solution is x=(ln(7))/(ln(21/5))