What is the answer to 3^{2x+1}=7 ?

The answer to 3^{2x+1}=7 is x=(ln(7)-ln(3))/(2ln(3))

Solve for x: 3^{2x+1}=7

The solution is x=(ln(7)-ln(3))/(2ln(3))

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3^{2 x + 1} = 7

x = \frac{ln ( 7 ) - ln ( 3 )}{2 ln ( 3 )}

Solution steps

3^{2 x + 1} = 7

Apply exponent rules

(2 x + 1) ln (3) = ln (7)

Solve

(2 x + 1) ln (3) = ln (7) : x = \frac{ln ( 7 ) - ln ( 3 )}{2 ln ( 3 )}

x = \frac{ln ( 7 ) - ln ( 3 )}{2 ln ( 3 )}

\frac{27}{1 + e ^{- x}} = 2

8^{2 x - 1} = \frac{1}{2} 32

4^{x + 1} - 5 (2^{x}) + 1 = 0

2^{x - 1} = \frac{1}{4}

What is the answer to 3^{2x+1}=7 ?
The answer to 3^{2x+1}=7 is x=(ln(7)-ln(3))/(2ln(3))
Solve for x: 3^{2x+1}=7
The solution is x=(ln(7)-ln(3))/(2ln(3))