What is the answer to 5-10^{2x}=0 ?

The answer to 5-10^{2x}=0 is x=(ln(5))/(2ln(10))

Solve for x: 5-10^{2x}=0

The solution is x=(ln(5))/(2ln(10))

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5 - 1 0^{2 x} = 0

x = \frac{ln ( 5 )}{2 ln ( 10 )}

Solution steps

5 - 1 0^{2 x} = 0

Add

1 0^{2 x}

to both sides

5 - 1 0^{2 x} + 1 0^{2 x} = 0 + 1 0^{2 x}

Simplify

5 = 1 0^{2 x}

Apply exponent rules

ln (5) = 2 x ln (10)

Solve

ln (5) = 2 x ln (10) : x = \frac{ln ( 5 )}{2 ln ( 10 )}

x = \frac{ln ( 5 )}{2 ln ( 10 )}

(2.79)^{x - 1} = 3.37 7^{x}

360 e^{- 0.06 t} = 240 e^{0.04 t}

2^{1 6^{x}} = 1 6^{2^{x}}

e^{6 - 4 x} = 8

(\frac{1}{9})^{x + 2} = 3

What is the answer to 5-10^{2x}=0 ?
The answer to 5-10^{2x}=0 is x=(ln(5))/(2ln(10))
Solve for x: 5-10^{2x}=0
The solution is x=(ln(5))/(2ln(10))