What is the answer to 2^n+2^n=2^{n+1} ?

The answer to 2^n+2^n=2^{n+1} is True for all n

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2^n+2^n=2^{n+1}

2^{n} + 2^{n} = 2^{n + 1}

True for all n

Solution steps

2^{n} + 2^{n} = 2^{n + 1}

Subtract

2^{n + 1}

from both sides

2^{n} + 2^{n} - 2^{n + 1} = 2^{n + 1} - 2^{n + 1}

Simplify

2 \cdot 2^{n} - 2^{n + 1} = 0

Add

2^{n + 1}

to both sides

2 \cdot 2^{n} - 2^{n + 1} + 2^{n + 1} = 0 + 2^{n + 1}

Simplify

2 \cdot 2^{n} = 2^{n + 1}

Apply exponent rules

n + 1 = n + 1

Both sides are equal

True for all n

5 \cdot 2^{x} + 2^{x + 2} = 18

x, e^{x} = \frac{y}{y - 2}

8^{2 x - 1} = \frac{1}{2 ^{x - 5}}

3^{2 x - 8} = 5^{2 x - 8}

4^{x} (8^{2 x - 1}) = 64

What is the answer to 2^n+2^n=2^{n+1} ?
The answer to 2^n+2^n=2^{n+1} is True for all n
Solve for n: 2^n+2^n=2^{n+1}
The solution is True for all n