What is the answer to 8^{2x-1}= 1/(2^{x-5)} ?

The answer to 8^{2x-1}= 1/(2^{x-5)} is x= 8/7

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8^{2x-1}= 1/(2^{x-5)}

8^{2 x - 1} = \frac{1}{2 ^{x - 5}}

x = \frac{8}{7}

Solution steps

8^{2 x - 1} = \frac{1}{2 ^{x - 5}}

Apply exponent rules

3 (2 x - 1) = - x + 5

Solve

3 (2 x - 1) = - x + 5 : x = \frac{8}{7}

x = \frac{8}{7}

Verify Solutions:

x = \frac{8}{7}

True

The solution is

x = \frac{8}{7}

3^{2 x - 8} = 5^{2 x - 8}

4^{x} (8^{2 x - 1}) = 64

4^{2 x} = 8^{x + 3}

5^{(3 - x)} = 125

3 2^{x - 2} = 8^{\frac{x + 6}{3}}

What is the answer to 8^{2x-1}= 1/(2^{x-5)} ?
The answer to 8^{2x-1}= 1/(2^{x-5)} is x= 8/7
Solve for x: 8^{2x-1}= 1/(2^{x-5)}
The solution is x= 8/7