What is the answer to (1/5)^{x-2}=25^{x-2} ?

The answer to (1/5)^{x-2}=25^{x-2} is x=2

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(1/5)^{x-2}=25^{x-2}

(\frac{1}{5})^{x - 2} = 2 5^{x - 2}

x = 2

Solution steps

(\frac{1}{5})^{x - 2} = 2 5^{x - 2}

Apply exponent rules

- (x - 2) = 2 (x - 2)

Solve

- (x - 2) = 2 (x - 2) : x = 2

x = 2

5^{x + 1} + 5^{x} + 5^{x - 2} - 151 = 0

2^{2 x} - 2^{x} - 12 = 0

4 + 3^{5 x} = 8

(\frac{1}{8})^{x + 3} = 1 6^{x - 4}

e^{\frac{2 x}{5}} = 25

What is the answer to (1/5)^{x-2}=25^{x-2} ?
The answer to (1/5)^{x-2}=25^{x-2} is x=2
Solve for x: (1/5)^{x-2}=25^{x-2}
The solution is x=2