What is the answer to -3+4*2^x=17 ?

The answer to -3+4*2^x=17 is x=(ln(5))/(ln(2))

Solve for x: -3+4*2^x=17

The solution is x=(ln(5))/(ln(2))

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- 3 + 4 \cdot 2^{x} = 17

x = \frac{ln ( 5 )}{ln ( 2 )}

Decimal Notation

x = 2.32192 \dots

Solution steps

- 3 + 4 \cdot 2^{x} = 17

Move

3

to the right side

4 \cdot 2^{x} = 20

Divide both sides by

4

2^{x} = 5

Apply exponent rules

x ln (2) = ln (5)

Solve

x ln (2) = ln (5) : x = \frac{ln ( 5 )}{ln ( 2 )}

x = \frac{ln ( 5 )}{ln ( 2 )}

x^{l n (x)} = e

3^{x + 1} = 9^{x}

e^{0.1 t} = 3

2^{x + 1} + (5) (2)^{x} = 28

4^{x + 1} = 1 6^{x - 1}

What is the answer to -3+4*2^x=17 ?
The answer to -3+4*2^x=17 is x=(ln(5))/(ln(2))
Solve for x: -3+4*2^x=17
The solution is x=(ln(5))/(ln(2))