What is the answer to 2^{x+1}+(5)(2)^x=28 ?

The answer to 2^{x+1}+(5)(2)^x=28 is x=2

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2^{x+1}+(5)(2)^x=28

2^{x + 1} + (5) (2)^{x} = 28

x = 2

Solution steps

2^{x + 1} + (5) (2)^{x} = 28

Factor

2^{x + 1} + 5 \cdot 2^{x} : 7 \cdot 2^{x}

7 \cdot 2^{x} = 28

Divide both sides by

7

2^{x} = 4

Apply exponent rules

x = 2

4^{x + 1} = 1 6^{x - 1}

(3)^{x} = 2 7^{x - 1}

4^{3 x} = 1 6^{2 - x}

4^{x} = 2^{\frac{8}{x}}

5^{x} = \frac{2}{5}

What is the answer to 2^{x+1}+(5)(2)^x=28 ?
The answer to 2^{x+1}+(5)(2)^x=28 is x=2
Solve for x: 2^{x+1}+(5)(2)^x=28
The solution is x=2