What is the answer to 5^{x+1}=10^x ?

The answer to 5^{x+1}=10^x is x=(ln(5))/(ln(2))

Solve for x: 5^{x+1}=10^x

The solution is x=(ln(5))/(ln(2))

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5^{x + 1} = 1 0^{x}

x = \frac{ln ( 5 )}{ln ( 2 )}

Solution steps

5^{x + 1} = 1 0^{x}

Apply exponent rules

(x + 1) ln (5) = x ln (10)

Solve

(x + 1) ln (5) = x ln (10) : x = \frac{ln ( 5 )}{ln ( 2 )}

x = \frac{ln ( 5 )}{ln ( 2 )}

2^{x + 2} = 8^{- x + 8}

x, 5 (1.08)^{x} = 20

e^{4 - 4 x} = 6

lo g_{2} (x^{l o g_{2} (x)}) = 4

e^{2 x + 1} = 5

What is the answer to 5^{x+1}=10^x ?
The answer to 5^{x+1}=10^x is x=(ln(5))/(ln(2))
Solve for x: 5^{x+1}=10^x
The solution is x=(ln(5))/(ln(2))