What is the answer to (10^x-1)(10^x+1)=0 ?

The answer to (10^x-1)(10^x+1)=0 is x=0

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(10^x-1)(10^x+1)=0

(1 0^{x} - 1) (1 0^{x} + 1) = 0

x = 0

Solution steps

(1 0^{x} - 1) (1 0^{x} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

1 0^{x} - 1 = 0 or 1 0^{x} + 1 = 0

Solve

1 0^{x} - 1 = 0 : x = 0

Solve

1 0^{x} + 1 = 0 :

No Solution for

x \in R

x = 0

4^{x} \cdot 3^{2 x} = 6

2^{n} = 1 0^{13}

4218.75 = 4000 (1 + 0.04)^{x}

3^{3 x + 1} = 8 1^{x - 1}

5^{x} = 2^{x + 1}

What is the answer to (10^x-1)(10^x+1)=0 ?
The answer to (10^x-1)(10^x+1)=0 is x=0
Solve for x: (10^x-1)(10^x+1)=0
The solution is x=0