What is the answer to 4^{x-1}=3 ?

The answer to 4^{x-1}=3 is x=(ln(3))/(2ln(2))+1

Solve for x: 4^{x-1}=3

The solution is x=(ln(3))/(2ln(2))+1

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4^{x - 1} = 3

x = \frac{ln ( 3 )}{2 ln ( 2 )} + 1

Decimal Notation

x = 1.79248 \dots

Solution steps

4^{x - 1} = 3

Apply exponent rules

(x - 1) ln (4) = ln (3)

Solve

(x - 1) ln (4) = ln (3) : x = \frac{ln ( 3 )}{2 ln ( 2 )} + 1

x = \frac{ln ( 3 )}{2 ln ( 2 )} + 1

x^{7} = 7^{x}

e^{1 - 2 x} = e^{3 x - 5}

8^{2 x + 3} = 2^{a} b^{x}

e^{5 l n (x)} = 32

(5)^{3 x - 1} = 4

What is the answer to 4^{x-1}=3 ?
The answer to 4^{x-1}=3 is x=(ln(3))/(2ln(2))+1
Solve for x: 4^{x-1}=3
The solution is x=(ln(3))/(2ln(2))+1