What is the answer to (sqrt(5))^{3x-1}=4 ?

The answer to (sqrt(5))^{3x-1}=4 is x=(ln(80))/(3ln(5))

Solve for x: (sqrt(5))^{3x-1}=4

The solution is x=(ln(80))/(3ln(5))

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(5)^{3 x - 1} = 4

x = \frac{ln ( 80 )}{3 ln ( 5 )}

Solution steps

(5)^{3 x - 1} = 4

Apply exponent rules

\frac{1}{2} (3 x - 1) ln (5) = ln (4)

Solve

\frac{1}{2} (3 x - 1) ln (5) = ln (4) : x = \frac{ln ( 80 )}{3 ln ( 5 )}

x = \frac{ln ( 80 )}{3 ln ( 5 )}

2^{3 x} = 7

3^{x} = e

1 + e^{4 x + 1} = 20

0. 5^{\frac{x}{10}} = \frac{1}{8}

8 1^{\frac{x}{4}} = \frac{1}{27}

What is the answer to (sqrt(5))^{3x-1}=4 ?
The answer to (sqrt(5))^{3x-1}=4 is x=(ln(80))/(3ln(5))
Solve for x: (sqrt(5))^{3x-1}=4
The solution is x=(ln(80))/(3ln(5))