What is the answer to 2^{3x}=7 ?

The answer to 2^{3x}=7 is x=(ln(7))/(3ln(2))

Solve for x: 2^{3x}=7

The solution is x=(ln(7))/(3ln(2))

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2^{3 x} = 7

x = \frac{ln ( 7 )}{3 ln ( 2 )}

Solution steps

2^{3 x} = 7

Apply exponent rules

3 x ln (2) = ln (7)

Solve

3 x ln (2) = ln (7) : x = \frac{ln ( 7 )}{3 ln ( 2 )}

x = \frac{ln ( 7 )}{3 ln ( 2 )}

3^{x} = e

1 + e^{4 x + 1} = 20

0. 5^{\frac{x}{10}} = \frac{1}{8}

8 1^{\frac{x}{4}} = \frac{1}{27}

3^{x + 1} (9^{2 - x}) = \frac{1}{3}