What is the answer to 3^{x+2}=5^{2x+7} ?

The answer to 3^{x+2}=5^{2x+7} is x=(7ln(5)-2ln(3))/(ln(3)-2ln(5))

Solve for x: 3^{x+2}=5^{2x+7}

The solution is x=(7ln(5)-2ln(3))/(ln(3)-2ln(5))

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3^{x + 2} = 5^{2 x + 7}

x = \frac{7 ln ( 5 ) - 2 ln ( 3 )}{ln ( 3 ) - 2 ln ( 5 )}

Decimal Notation

x = - 4.27722 \dots

Solution steps

3^{x + 2} = 5^{2 x + 7}

Apply exponent rules

(x + 2) ln (3) = (2 x + 7) ln (5)

Solve

(x + 2) ln (3) = (2 x + 7) ln (5) : x = \frac{7 ln ( 5 ) - 2 ln ( 3 )}{ln ( 3 ) - 2 ln ( 5 )}

x = \frac{7 ln ( 5 ) - 2 ln ( 3 )}{ln ( 3 ) - 2 ln ( 5 )}

3^{2 x + 1} = 3^{π x + 4}

e^{x} + x - 1 = 0

5^{6 x} - 6 (12 5^{x}) + 5 = 0

4 \cdot 2^{x} = 2^{6 x + 3}

9^{2 - x} = (\frac{1}{3})^{2 x + 1}

What is the answer to 3^{x+2}=5^{2x+7} ?
The answer to 3^{x+2}=5^{2x+7} is x=(7ln(5)-2ln(3))/(ln(3)-2ln(5))
Solve for x: 3^{x+2}=5^{2x+7}
The solution is x=(7ln(5)-2ln(3))/(ln(3)-2ln(5))