What is the answer to 9^{2-x}=(1/3)^{2x+1} ?

The answer to 9^{2-x}=(1/3)^{2x+1} is No Solution for x\in\mathbb{R}

Solve for x: 9^{2-x}=(1/3)^{2x+1}

The solution is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9^{2 - x} = (\frac{1}{3})^{2 x + 1}

No Solution for x \in R

Solution steps

9^{2 - x} = (\frac{1}{3})^{2 x + 1}

Apply exponent rules

2 (2 - x) = - (2 x + 1)

Solve

2 (2 - x) = - (2 x + 1) :

No Solution

No Solution for x \in R

(\frac{1}{4})^{x} = 4

(2)^{k} = 0.25

3^{2 x} - 10 (3^{x}) + 9 = 0

9^{x} = 2 7^{- 6}

x, e^{x} + x e^{x} = 0

What is the answer to 9^{2-x}=(1/3)^{2x+1} ?
The answer to 9^{2-x}=(1/3)^{2x+1} is No Solution for x\in\mathbb{R}
Solve for x: 9^{2-x}=(1/3)^{2x+1}
The solution is No Solution for x\in\mathbb{R}