What is the answer to 3^{2x}-10(3^x)+9=0 ?

The answer to 3^{2x}-10(3^x)+9=0 is x=2,x=0

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3^{2x}-10(3^x)+9=0

3^{2 x} - 10 (3^{x}) + 9 = 0

x = 2, x = 0

Solution steps

3^{2 x} - 10 (3^{x}) + 9 = 0

Apply exponent rules

(3^{x})^{2} - 10 \cdot 3^{x} + 9 = 0

Rewrite the equation with

3^{x} = u

(u)^{2} - 10 u + 9 = 0

Solve

u^{2} - 10 u + 9 = 0 : u = 9, u = 1

u = 9, u = 1

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 9 : x = 2

Solve

3^{x} = 1 : x = 0

x = 2, x = 0

9^{x} = 2 7^{- 6}

x, e^{x} + x e^{x} = 0

e^{x + 1} = 30

e^{8.5 n} - 4 = 41

3^{x + 2} = 5^{x}

What is the answer to 3^{2x}-10(3^x)+9=0 ?
The answer to 3^{2x}-10(3^x)+9=0 is x=2,x=0
Solve for x: 3^{2x}-10(3^x)+9=0
The solution is x=2,x=0