What is the answer to 3^{x+2}=5^x ?

The answer to 3^{x+2}=5^x is x=(2ln(3))/(ln(5)-ln(3))

Solve for x: 3^{x+2}=5^x

The solution is x=(2ln(3))/(ln(5)-ln(3))

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3^{x + 2} = 5^{x}

x = \frac{2 ln ( 3 )}{ln ( 5 ) - ln ( 3 )}

Solution steps

3^{x + 2} = 5^{x}

Apply exponent rules

(x + 2) ln (3) = x ln (5)

Solve

(x + 2) ln (3) = x ln (5) : x = \frac{2 ln ( 3 )}{ln ( 5 ) - ln ( 3 )}

x = \frac{2 ln ( 3 )}{ln ( 5 ) - ln ( 3 )}

(\frac{1}{3}) (3^{2 x - 1}) = 9

e^{9 x} = 9 e^{x}

10 e^{- 2 x} = 2

2^{x} \cdot 4^{1 - x} = 5^{2 - x}

e^{3 x - 6} = 14

What is the answer to 3^{x+2}=5^x ?
The answer to 3^{x+2}=5^x is x=(2ln(3))/(ln(5)-ln(3))
Solve for x: 3^{x+2}=5^x
The solution is x=(2ln(3))/(ln(5)-ln(3))