What is the answer to 3^{2(x+1)}-28(3^x)+3=0 ?

The answer to 3^{2(x+1)}-28(3^x)+3=0 is x=1,x=-2

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3^{2(x+1)}-28(3^x)+3=0

3^{2 (x + 1)} - 28 (3^{x}) + 3 = 0

x = 1, x = - 2

Solution steps

3^{2 (x + 1)} - 28 (3^{x}) + 3 = 0

Apply exponent rules

(3^{x})^{2} \cdot 3^{2} - 28 \cdot 3^{x} + 3 = 0

Rewrite the equation with

3^{x} = u

(u)^{2} \cdot 3^{2} - 28 u + 3 = 0

Solve

u^{2} \cdot 3^{2} - 28 u + 3 = 0 : u = 3, u = \frac{1}{9}

u = 3, u = \frac{1}{9}

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 3 : x = 1

Solve

3^{x} = \frac{1}{9} : x = - 2

x = 1, x = - 2

e^{x + l n (2)} - 15 e^{- x} = - 1

x e^{- x} = 0

3^{x + 6} = 3^{4}

9^{2 x} \cdot 2 7^{x^{2}} = 3^{- 1}

What is the answer to 3^{2(x+1)}-28(3^x)+3=0 ?
The answer to 3^{2(x+1)}-28(3^x)+3=0 is x=1,x=-2
Solve for x: 3^{2(x+1)}-28(3^x)+3=0
The solution is x=1,x=-2