What is the answer to 3^{x+9}=12 ?

The answer to 3^{x+9}=12 is x=(ln(12))/(ln(3))-9

Solve for x: 3^{x+9}=12

The solution is x=(ln(12))/(ln(3))-9

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3^{x + 9} = 12

x = \frac{ln ( 12 )}{ln ( 3 )} - 9

Decimal Notation

x = - 6.73814 \dots

Solution steps

3^{x + 9} = 12

Apply exponent rules

(x + 9) ln (3) = ln (12)

Solve

(x + 9) ln (3) = ln (12) : x = \frac{ln ( 12 )}{ln ( 3 )} - 9

x = \frac{ln ( 12 )}{ln ( 3 )} - 9

A = 50 e^{0.07 t}

1 6^{x + 1} = 8^{2 x + 1}

e^{x} - x^{3} = 0

4^{3 x} = 8^{x - 1}

What is the answer to 3^{x+9}=12 ?
The answer to 3^{x+9}=12 is x=(ln(12))/(ln(3))-9
Solve for x: 3^{x+9}=12
The solution is x=(ln(12))/(ln(3))-9