What is the answer to 3^x=5^{x+2} ?

The answer to 3^x=5^{x+2} is x=(2ln(5))/(ln(3)-ln(5))

Solve for x: 3^x=5^{x+2}

The solution is x=(2ln(5))/(ln(3)-ln(5))

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3^{x} = 5^{x + 2}

x = \frac{2 ln ( 5 )}{ln ( 3 ) - ln ( 5 )}

Solution steps

3^{x} = 5^{x + 2}

Apply exponent rules

x ln (3) = (x + 2) ln (5)

Solve

x ln (3) = (x + 2) ln (5) : x = \frac{2 ln ( 5 )}{ln ( 3 ) - ln ( 5 )}

x = \frac{2 ln ( 5 )}{ln ( 3 ) - ln ( 5 )}

(a^{3})^{6} = (a^{2})^{x}

x, 4^{x + 1} + 2^{y} = 20

t, (1.045)^{t} = 2

x, 1 0^{- 6 x} = 10 0^{3 - 2 x}

3 \cdot 2^{x + 1} - 64 = 2^{x + 1}

What is the answer to 3^x=5^{x+2} ?
The answer to 3^x=5^{x+2} is x=(2ln(5))/(ln(3)-ln(5))
Solve for x: 3^x=5^{x+2}
The solution is x=(2ln(5))/(ln(3)-ln(5))