What is the answer to 3*2^{x+1}-64=2^{x+1} ?

The answer to 3*2^{x+1}-64=2^{x+1} is x=4

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3*2^{x+1}-64=2^{x+1}

3 \cdot 2^{x + 1} - 64 = 2^{x + 1}

x = 4

Solution steps

3 \cdot 2^{x + 1} - 64 = 2^{x + 1}

Move

64

to the right side

3 \cdot 2^{x + 1} = 2^{x + 1} + 64

Move

2^{x + 1}

to the left side

2 \cdot 2^{x + 1} = 64

Divide both sides by

2

2^{x + 1} = 32

Apply exponent rules

x + 1 = 5

Solve

x + 1 = 5 : x = 4

x = 4

(5)^{x} = 125

2^{2 x + 1} = 2^{4}

(\frac{1}{2})^{x} = 0.9

2^{2 x + 1} = 4^{x} + 64

What is the answer to 3*2^{x+1}-64=2^{x+1} ?
The answer to 3*2^{x+1}-64=2^{x+1} is x=4
Solve for x: 3*2^{x+1}-64=2^{x+1}
The solution is x=4