What is the answer to 3(5)^{x+2}=8^{1-x} ?

The answer to 3(5)^{x+2}=8^{1-x} is x=(3ln(2)-ln(75))/(ln(40))

Solve for x: 3(5)^{x+2}=8^{1-x}

The solution is x=(3ln(2)-ln(75))/(ln(40))

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3 (5)^{x + 2} = 8^{1 - x}

x = \frac{3 ln ( 2 ) - ln ( 75 )}{ln ( 40 )}

Solution steps

3 (5)^{x + 2} = 8^{1 - x}

Apply exponent rules

ln (3) + (x + 2) ln (5) = (1 - x) ln (8)

Solve

ln (3) + (x + 2) ln (5) = (1 - x) ln (8) : x = \frac{3 ln ( 2 ) - ln ( 75 )}{ln ( 40 )}

x = \frac{3 ln ( 2 ) - ln ( 75 )}{ln ( 40 )}

x, y e^{x y} = 0

2 5^{y + 2} = 5^{y - 4} \cdot 12 5^{y}

\frac{4 ^{x - 1}}{2 ^{x + 2}} = 186

4 \cdot 7^{2 x} = 9

e^{x - 3} + e^{- x + 3} = 22

What is the answer to 3(5)^{x+2}=8^{1-x} ?
The answer to 3(5)^{x+2}=8^{1-x} is x=(3ln(2)-ln(75))/(ln(40))
Solve for x: 3(5)^{x+2}=8^{1-x}
The solution is x=(3ln(2)-ln(75))/(ln(40))