What is the answer to (1/8)^x=16^{x-3} ?

The answer to (1/8)^x=16^{x-3} is x= 12/7

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(1/8)^x=16^{x-3}

(\frac{1}{8})^{x} = 1 6^{x - 3}

x = \frac{12}{7}

Solution steps

(\frac{1}{8})^{x} = 1 6^{x - 3}

Apply exponent rules

- 3 x = 4 (x - 3)

Solve

- 3 x = 4 (x - 3) : x = \frac{12}{7}

x = \frac{12}{7}

(0.5)^{x} = 2

e^{t} = 1

e^{x} = e^{3 x + 8}

4 9^{x + 1} = 7

3^{x^{2}} = \frac{27}{9 ^{x}}

What is the answer to (1/8)^x=16^{x-3} ?
The answer to (1/8)^x=16^{x-3} is x= 12/7
Solve for x: (1/8)^x=16^{x-3}
The solution is x= 12/7