What is the answer to 2^{4x}=127 ?

The answer to 2^{4x}=127 is x=(ln(127))/(4ln(2))

Solve for x: 2^{4x}=127

The solution is x=(ln(127))/(4ln(2))

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2^{4 x} = 127

x = \frac{ln ( 127 )}{4 ln ( 2 )}

Decimal Notation

x = 1.74717 \dots

Solution steps

2^{4 x} = 127

Apply exponent rules

4 x ln (2) = ln (127)

Solve

4 x ln (2) = ln (127) : x = \frac{ln ( 127 )}{4 ln ( 2 )}

x = \frac{ln ( 127 )}{4 ln ( 2 )}

x, e^{x} = 7

2 5^{x} - 23 \cdot 5^{x} = 50

(\frac{1}{81})^{3 x - 5} = 243

9^{2 x} = 81

m = 0.9 e^{- 0.06 t}

What is the answer to 2^{4x}=127 ?
The answer to 2^{4x}=127 is x=(ln(127))/(4ln(2))
Solve for x: 2^{4x}=127
The solution is x=(ln(127))/(4ln(2))