What is the answer to (2^{6x+3})(4^{3x+6})=8^{4x+5} ?

The answer to (2^{6x+3})(4^{3x+6})=8^{4x+5} is True for all x

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(2^{6x+3})(4^{3x+6})=8^{4x+5}

(2^{6 x + 3}) (4^{3 x + 6}) = 8^{4 x + 5}

True for all x

Solution steps

(2^{6 x + 3}) (4^{3 x + 6}) = 8^{4 x + 5}

Apply exponent rules

6 x + 3 + 2 (3 x + 6) = 3 (4 x + 5)

Solve

6 x + 3 + 2 (3 x + 6) = 3 (4 x + 5) :

True for all

x

True for all x

5 \cdot 4^{v - 1} = 92.8

x, 3^{2 x} + 1 + 4 (3 x) - 15 = 0

x e^{2 x} = x e^{x + 3}

3^{3 n} \cdot 9^{- 2 n + 1} = 27

2 = 1. 1^{t}

What is the answer to (2^{6x+3})(4^{3x+6})=8^{4x+5} ?
The answer to (2^{6x+3})(4^{3x+6})=8^{4x+5} is True for all x
Solve for x: (2^{6x+3})(4^{3x+6})=8^{4x+5}
The solution is True for all x