What is the answer to 7^{5x+4}=21 ?

The answer to 7^{5x+4}=21 is x=(ln(3/343))/(5ln(7))

Solve for x: 7^{5x+4}=21

The solution is x=(ln(3/343))/(5ln(7))

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7^{5 x + 4} = 21

x = \frac{ln ( \frac{3}{343} )}{5 ln ( 7 )}

Decimal Notation

x = - 0.48708 \dots

Solution steps

7^{5 x + 4} = 21

Apply exponent rules

(5 x + 4) ln (7) = ln (21)

Solve

(5 x + 4) ln (7) = ln (21) : x = \frac{ln ( \frac{3}{343} )}{5 ln ( 7 )}

x = \frac{ln ( \frac{3}{343} )}{5 ln ( 7 )}

3^{4^{x + 3}} = 3^{1 6^{2 x - 5}}

110624.8 = 55000 \cdot (1.15)^{x}

3^{x - x^{2}} = \frac{1}{9 ^{x}}

7^{x} = 4 9^{2}

e^{x} = - \frac{1}{2}

What is the answer to 7^{5x+4}=21 ?
The answer to 7^{5x+4}=21 is x=(ln(3/343))/(5ln(7))
Solve for x: 7^{5x+4}=21
The solution is x=(ln(3/343))/(5ln(7))