What is the answer to 2^{x-5}=3^{4x+1} ?

The answer to 2^{x-5}=3^{4x+1} is x=(ln(96))/(ln(2)-4ln(3))

Solve for x: 2^{x-5}=3^{4x+1}

The solution is x=(ln(96))/(ln(2)-4ln(3))

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2^{x - 5} = 3^{4 x + 1}

x = \frac{ln ( 96 )}{ln ( 2 ) - 4 ln ( 3 )}

Decimal Notation

x = - 1.23317 \dots

Solution steps

2^{x - 5} = 3^{4 x + 1}

Apply exponent rules

(x - 5) ln (2) = (4 x + 1) ln (3)

Solve

(x - 5) ln (2) = (4 x + 1) ln (3) : x = \frac{ln ( 96 )}{ln ( 2 ) - 4 ln ( 3 )}

x = \frac{ln ( 96 )}{ln ( 2 ) - 4 ln ( 3 )}

2^{x} = 5^{1 - x}

2^{3 x - 5} = 1024

e^{t^{2}} = 4

e^{(x^{2} - 16)} = 20

e^{x} = 100

What is the answer to 2^{x-5}=3^{4x+1} ?
The answer to 2^{x-5}=3^{4x+1} is x=(ln(96))/(ln(2)-4ln(3))
Solve for x: 2^{x-5}=3^{4x+1}
The solution is x=(ln(96))/(ln(2)-4ln(3))