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Popular >

log_{6}(4e^{y-1})=2

Solution

lo g_{6} (4 e^{y - 1}) = 2

Solution

y = 2 ln (3) + 1

+1

Decimal Notation

y = 3.19722 \dots

Solution steps

lo g_{6} (4 e^{y - 1}) = 2

Rewrite the equation with

e^{y - 1} = u

lo g_{6} (4 u) = 2

Solve

lo g_{6} (4 u) = 2 : u = 9

u = 9

Substitute back

u = e^{y - 1},

solve for

y

Solve

e^{y - 1} = 9 : y = 2 ln (3) + 1

y = 2 ln (3) + 1

Popular Examples

0. 4^{x} = 0

3^{x} 2^{1 - x} = 10

0 = - e^{3 x} + 3

x^{x} (ln (x) + 1) = 0

4^{x^2}*4^{5x-3}=64

4^{x^{2}} \cdot 4^{5 x - 3} = 64

Frequently Asked Questions (FAQ)

What is the answer to log_{6}(4e^{y-1})=2 ?
The answer to log_{6}(4e^{y-1})=2 is y=2ln(3)+1