What is the answer to 2^{2x}=3 ?

The answer to 2^{2x}=3 is x=(ln(3))/(2ln(2))

Solve for x: 2^{2x}=3

The solution is x=(ln(3))/(2ln(2))

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2^{2 x} = 3

x = \frac{ln ( 3 )}{2 ln ( 2 )}

Decimal Notation

x = 0.79248 \dots

Solution steps

2^{2 x} = 3

Apply exponent rules

2 x ln (2) = ln (3)

Solve

2 x ln (2) = ln (3) : x = \frac{ln ( 3 )}{2 ln ( 2 )}

x = \frac{ln ( 3 )}{2 ln ( 2 )}

2^{x^{2} + x} = 4

6^{x - 2} = \frac{1}{4}

500 = 30 e^{x}

5^{x + 2} = 7^{2 x + 1}

4^{x + 6} = 7