What is the answer to 4^{x+6}=7 ?

The answer to 4^{x+6}=7 is x=(ln(7))/(2ln(2))-6

Solve for x: 4^{x+6}=7

The solution is x=(ln(7))/(2ln(2))-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4^{x + 6} = 7

x = \frac{ln ( 7 )}{2 ln ( 2 )} - 6

Decimal Notation

x = - 4.59632 \dots

Solution steps

4^{x + 6} = 7

Apply exponent rules

(x + 6) ln (4) = ln (7)

Solve

(x + 6) ln (4) = ln (7) : x = \frac{ln ( 7 )}{2 ln ( 2 )} - 6

x = \frac{ln ( 7 )}{2 ln ( 2 )} - 6

4^{3 x + 5} = 16

5^{1 - 2 x} = \frac{1}{5}

4^{x + 2} + 8 \cdot 2^{x + 2} = 128

1 6^{3 - x} = (\frac{1}{2})^{2 x + 4}

5^{x - 2} = 4^{2 x + 3}

What is the answer to 4^{x+6}=7 ?
The answer to 4^{x+6}=7 is x=(ln(7))/(2ln(2))-6
Solve for x: 4^{x+6}=7
The solution is x=(ln(7))/(2ln(2))-6