What is the answer to 5^{x-2}=4^{2x+3} ?

The answer to 5^{x-2}=4^{2x+3} is x=(2ln(40))/(ln(5)-4ln(2))

Solve for x: 5^{x-2}=4^{2x+3}

The solution is x=(2ln(40))/(ln(5)-4ln(2))

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5^{x - 2} = 4^{2 x + 3}

x = \frac{2 ln ( 40 )}{ln ( 5 ) - 4 ln ( 2 )}

Decimal Notation

x = - 6.34290 \dots

Solution steps

5^{x - 2} = 4^{2 x + 3}

Apply exponent rules

(x - 2) ln (5) = (2 x + 3) ln (4)

Solve

(x - 2) ln (5) = (2 x + 3) ln (4) : x = \frac{2 ln ( 40 )}{ln ( 5 ) - 4 ln ( 2 )}

x = \frac{2 ln ( 40 )}{ln ( 5 ) - 4 ln ( 2 )}

3 2^{3 p + 2} = 1 6^{p - 1}

3^{2 (x + 1)} - 18 \cdot 3^{x} + 9 = 0

2^{x} - 2^{x - 2} = 3 (2^{13})

3 e^{2 x} = 4.2

4^{x} + 1 = 2^{x + 1}

What is the answer to 5^{x-2}=4^{2x+3} ?
The answer to 5^{x-2}=4^{2x+3} is x=(2ln(40))/(ln(5)-4ln(2))
Solve for x: 5^{x-2}=4^{2x+3}
The solution is x=(2ln(40))/(ln(5)-4ln(2))