What is the answer to 5^x=3^{x-1} ?

The answer to 5^x=3^{x-1} is x=-(ln(3))/(ln(5)-ln(3))

Solve for x: 5^x=3^{x-1}

The solution is x=-(ln(3))/(ln(5)-ln(3))

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5^{x} = 3^{x - 1}

x = - \frac{ln ( 3 )}{ln ( 5 ) - ln ( 3 )}

Decimal Notation

x = - 2.15066 \dots

Solution steps

5^{x} = 3^{x - 1}

Apply exponent rules

x ln (5) = (x - 1) ln (3)

Solve

x ln (5) = (x - 1) ln (3) : x = - \frac{ln ( 3 )}{ln ( 5 ) - ln ( 3 )}

x = - \frac{ln ( 3 )}{ln ( 5 ) - ln ( 3 )}

2^{x^{2} - 1} = 8

5^{2 x + 1} = 25

1.0 1^{x} = 2

x, y + e^{y} = (x + C) e^{- x}

What is the answer to 5^x=3^{x-1} ?
The answer to 5^x=3^{x-1} is x=-(ln(3))/(ln(5)-ln(3))
Solve for x: 5^x=3^{x-1}
The solution is x=-(ln(3))/(ln(5)-ln(3))