What is the answer to 27=10^{x+4} ?

The answer to 27=10^{x+4} is x=(3ln(3))/(ln(10))-4

Solve for x: 27=10^{x+4}

The solution is x=(3ln(3))/(ln(10))-4

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27 = 1 0^{x + 4}

x = \frac{3 ln ( 3 )}{ln ( 10 )} - 4

Decimal Notation

x = - 2.56863 \dots

Solution steps

27 = 1 0^{x + 4}

Apply exponent rules

ln (27) = (x + 4) ln (10)

Solve

ln (27) = (x + 4) ln (10) : x = \frac{3 ln ( 3 )}{ln ( 10 )} - 4

x = \frac{3 ln ( 3 )}{ln ( 10 )} - 4

2 (7^{y}) = 3 - 5 7^{y}

- 2 = 2^{x}

16 = 5 + 16 e^{34 k}

3^{y} = \frac{1}{81}

3^{2 x} - 6 \cdot 3^{x} + 8 = 0

What is the answer to 27=10^{x+4} ?
The answer to 27=10^{x+4} is x=(3ln(3))/(ln(10))-4
Solve for x: 27=10^{x+4}
The solution is x=(3ln(3))/(ln(10))-4