What is the answer to 79=35^x ?

The answer to 79=35^x is x=(ln(79))/(ln(35))

The solution is x=(ln(79))/(ln(35))

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79=35^x

79 = 3 5^{x}

x = \frac{ln ( 79 )}{ln ( 35 )}

Decimal Notation

x = 1.22897 \dots

Solution steps

79 = 3 5^{x}

Apply exponent rules

ln (79) = x ln (35)

Solve

ln (79) = x ln (35) : x = \frac{ln ( 79 )}{ln ( 35 )}

x = \frac{ln ( 79 )}{ln ( 35 )}

e^{(x^{2} + 2 x + 1)} = 1

5^{3 x} = 12 5^{2 x - 3}

7^{2 x + 3} = 7^{15}

2^{1 - x} = \frac{9}{4}

y, z = x^{y - w}