What is the answer to 2^{1-x}= 9/4 ?

The answer to 2^{1-x}= 9/4 is x=-(ln(9/4)-ln(2))/(ln(2))

Solve for x: 2^{1-x}= 9/4

The solution is x=-(ln(9/4)-ln(2))/(ln(2))

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2^{1 - x} = \frac{9}{4}

x = - \frac{ln ( \frac{9}{4} ) - ln ( 2 )}{ln ( 2 )}

Decimal Notation

x = - 0.16992 \dots

Solution steps

2^{1 - x} = \frac{9}{4}

Apply exponent rules

(1 - x) ln (2) = ln (\frac{9}{4})

Solve

(1 - x) ln (2) = ln (\frac{9}{4}) : x = - \frac{ln ( \frac{9}{4} ) - ln ( 2 )}{ln ( 2 )}

x = - \frac{ln ( \frac{9}{4} ) - ln ( 2 )}{ln ( 2 )}

y, z = x^{y - w}

16 (4^{2 x}) - 65 (4^{x}) + 4 = 0

4^{1 + 2 x} \cdot 3^{4 x + 1} = 432

x, 4 - 3^{x} = 0

128 = 2^{n}

What is the answer to 2^{1-x}= 9/4 ?
The answer to 2^{1-x}= 9/4 is x=-(ln(9/4)-ln(2))/(ln(2))
Solve for x: 2^{1-x}= 9/4
The solution is x=-(ln(9/4)-ln(2))/(ln(2))