What is the answer to 2^{x+1}*4^{x+2}=8 ?

The answer to 2^{x+1}*4^{x+2}=8 is x=-2/3

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2^{x+1}*4^{x+2}=8

2^{x + 1} \cdot 4^{x + 2} = 8

x = - \frac{2}{3}

Decimal Notation

x = - 0.66666 \dots

Solution steps

2^{x + 1} \cdot 4^{x + 2} = 8

Apply exponent rules

3 (x + 1) = 1

Solve

3 (x + 1) = 1 : x = - \frac{2}{3}

x = - \frac{2}{3}

9^{8 - 3 x} = (3^{2})^{2 x - 2}

e^{3 k} = 5

e^{4 x} = 6

8^{- x} = 2

3 (2.25)^{4 x} = 5 (4^{0.3 x - 2.2})

What is the answer to 2^{x+1}*4^{x+2}=8 ?
The answer to 2^{x+1}*4^{x+2}=8 is x=-2/3
Solve for x: 2^{x+1}*4^{x+2}=8
The solution is x=-2/3