What is the answer to 3(2.25)^{4x}=5(4^{0.3x-2.2}) ?

The answer to 3(2.25)^{4x}=5(4^{0.3x-2.2}) is x=(ln(5)-ln(3*2^{4.4}))/(4ln(2.25)-0.6ln(2))

Solve for x: 3(2.25)^{4x}=5(4^{0.3x-2.2})

The solution is x=(ln(5)-ln(3*2^{4.4}))/(4ln(2.25)-0.6ln(2))

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3 (2.25)^{4 x} = 5 (4^{0.3 x - 2.2})

x = \frac{ln ( 5 ) - ln ( 3 \cdot 2 ^{4.4} )}{4 ln ( 2.25 ) - 0.6 ln ( 2 )}

Decimal Notation

x = - 0.89786 \dots

Solution steps

3 (2.25)^{4 x} = 5 (4^{0.3 x - 2.2})

Apply exponent rules

ln (3) + 4 x ln (2.25) = ln (5) + (0.3 x - 2.2) ln (4)

Solve

ln (3) + 4 x ln (2.25) = ln (5) + (0.3 x - 2.2) ln (4) : x = \frac{ln ( 5 ) - ln ( 3 \cdot 2 ^{4.4} )}{4 ln ( 2.25 ) - 0.6 ln ( 2 )}

x = \frac{ln ( 5 ) - ln ( 3 \cdot 2 ^{4.4} )}{4 ln ( 2.25 ) - 0.6 ln ( 2 )}

2^{x} = (8)^{5}

x, 2^{x} + 3^{y} = z^{2}

2^{2 x - 1} = 5^{3 - x}

4^{x + 3} = 6^{x}

16 - 5 \cdot 2^{x} + 4^{x - 1} = 0

What is the answer to 3(2.25)^{4x}=5(4^{0.3x-2.2}) ?
The answer to 3(2.25)^{4x}=5(4^{0.3x-2.2}) is x=(ln(5)-ln(3*2^{4.4}))/(4ln(2.25)-0.6ln(2))
Solve for x: 3(2.25)^{4x}=5(4^{0.3x-2.2})
The solution is x=(ln(5)-ln(3*2^{4.4}))/(4ln(2.25)-0.6ln(2))