What is the answer to 50=73+(36-73)e^{-k(45)} ?

The answer to 50=73+(36-73)e^{-k(45)} is k=-(ln(23/37))/(45)

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50=73+(36-73)e^{-k(45)}

50 = 73 + (36 - 73) e^{- k (45)}

k = - \frac{ln ( \frac{23}{37} )}{45}

Decimal Notation

k = 0.01056 \dots

Solution steps

50 = 73 + (36 - 73) e^{- k (45)}

Switch sides

73 + (36 - 73) e^{- k 45} = 50

(36 - 73) e^{- k 45} = - 37 e^{- k 45}

73 - 37 e^{- k 45} = 50

Move

73

to the right side

- 37 e^{- k 45} = - 23

Divide both sides by

- 37

e^{- k 45} = \frac{23}{37}

Apply exponent rules

- k \cdot 45 = ln (\frac{23}{37})

Solve

- k \cdot 45 = ln (\frac{23}{37}) : k = - \frac{ln ( \frac{23}{37} )}{45}

k = - \frac{ln ( \frac{23}{37} )}{45}

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16 = 2^{x - 3}

x, e^{x y} + x y = 2

7^{5 x + 7} = 3

1 1^{2 x} = 12 1^{3 x + 1}

What is the answer to 50=73+(36-73)e^{-k(45)} ?
The answer to 50=73+(36-73)e^{-k(45)} is k=-(ln(23/37))/(45)