What is the answer to (3/2)^x=4^{(1-x)} ?

The answer to (3/2)^x=4^{(1-x)} is x=(2ln(2))/(ln(6))

Solve for x: (3/2)^x=4^{(1-x)}

The solution is x=(2ln(2))/(ln(6))

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(\frac{3}{2})^{x} = 4^{(1 - x)}

x = \frac{2 ln ( 2 )}{ln ( 6 )}

Decimal Notation

x = 0.77370 \dots

Solution steps

(\frac{3}{2})^{x} = 4^{(1 - x)}

Apply exponent rules

x ln (\frac{3}{2}) = (1 - x) ln (4)

Solve

x ln (\frac{3}{2}) = (1 - x) ln (4) : x = \frac{2 ln ( 2 )}{ln ( 6 )}

x = \frac{2 ln ( 2 )}{ln ( 6 )}

7^{x} = \frac{1}{49}

e^{(- x + 1)} = 15

8^{6 x^{2} + 4 x} = 4^{9 x^{2} - 9 x + 6}

0. 1^{x} = 10

n, (1 + i)^{n} = 32 i

What is the answer to (3/2)^x=4^{(1-x)} ?
The answer to (3/2)^x=4^{(1-x)} is x=(2ln(2))/(ln(6))
Solve for x: (3/2)^x=4^{(1-x)}
The solution is x=(2ln(2))/(ln(6))